{"product_id":"black-white-diamond-oval-split-shank-ring-in-14k-white-gold","title":"2-1\/4ct. T.W. Black \u0026 White Diamond Oval Split Shank Ring in 14k White Gold","description":"Experience the enchanting allure of this Black and White Diamond Ring. Meticulously crafted in 14k white gold, this exquisite piece boasts a captivating composition of an oval-cut black diamond at the center and round black and white diamonds along the split style band. The artful split-shank design and stunning oval-cut black diamond create an atmosphere of sophistication, making it an ideal choice for an engagement ring or a distinctive fashion statement. This ring is a remarkable anniversary gift, seamlessly blending classic and contemporary elements.\u003cli\u003eSet in 14k White Gold\u003c\/li\u003e\u003cli\u003eBlack Rhodium Plating along prongs\u003c\/li\u003e\u003cli\u003e2 1\/4 ct. t.w. Black \u0026amp; White Diamond\u003c\/li\u003e\u003cli\u003eDiamond Color: Black\/G-H\u003c\/li\u003e\u003cli\u003eDiamond Clarity: I1-I2\u003c\/li\u003e\u003cli\u003eDiamond Shape: Oval, Round\u003c\/li\u003e\u003cli\u003eHigh Polish Finish\u003c\/li\u003e","brand":"Lord \u0026 Taylor Fine Jewelry","offers":[{"title":"5","offer_id":54006274687265,"sku":"LT2000823-5","price":5335.0,"currency_code":"USD","in_stock":true},{"title":"6","offer_id":54006274720033,"sku":"LT2000823-6","price":5335.0,"currency_code":"USD","in_stock":true},{"title":"7","offer_id":54006274752801,"sku":"LT2000823-7","price":5335.0,"currency_code":"USD","in_stock":true},{"title":"8","offer_id":54006274785569,"sku":"LT2000823-8","price":5335.0,"currency_code":"USD","in_stock":true},{"title":"9","offer_id":54006274818337,"sku":"LT2000823-9","price":5335.0,"currency_code":"USD","in_stock":true}],"thumbnail_url":"\/\/cdn.shopify.com\/s\/files\/1\/0906\/3789\/3921\/files\/01a15af1-c0b7-70b0-95aa-4c27fecedebe.jpg?v=1792696485","url":"https:\/\/lordandtaylor.com\/products\/black-white-diamond-oval-split-shank-ring-in-14k-white-gold","provider":"Lord \u0026 Taylor","version":"1.0","type":"link"}